3x^2+2(x^2-20)=16-2x^2

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Solution for 3x^2+2(x^2-20)=16-2x^2 equation: 


Simplifying
3x2 + 2(x2 + -20) = 16 + -2x2

Reorder the terms:
3x2 + 2(-20 + x2) = 16 + -2x2
3x2 + (-20 * 2 + x2 * 2) = 16 + -2x2
3x2 + (-40 + 2x2) = 16 + -2x2

Reorder the terms:
-40 + 3x2 + 2x2 = 16 + -2x2

Combine like terms: 3x2 + 2x2 = 5x2
-40 + 5x2 = 16 + -2x2

Solving
-40 + 5x2 = 16 + -2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2x2' to each side of the equation.
-40 + 5x2 + 2x2 = 16 + -2x2 + 2x2

Combine like terms: 5x2 + 2x2 = 7x2
-40 + 7x2 = 16 + -2x2 + 2x2

Combine like terms: -2x2 + 2x2 = 0
-40 + 7x2 = 16 + 0
-40 + 7x2 = 16

Add '40' to each side of the equation.
-40 + 40 + 7x2 = 16 + 40

Combine like terms: -40 + 40 = 0
0 + 7x2 = 16 + 40
7x2 = 16 + 40

Combine like terms: 16 + 40 = 56
7x2 = 56

Divide each side by '7'.
x2 = 8

Simplifying
x2 = 8

Take the square root of each side:
x = {-2.828427125, 2.828427125}

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